Python Variable Scope

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What does the following code print? x = 55 def hi(): return x print(hi())	`55` is printed. The variable `x` is defined in the global scope. Global variables are accessible anywhere in the program, including the local function scope.
What does the following code print? def pointless(): z = 77 return z print(pointless())	`77` is printed. The variable `z` is defined in a local scope for the `pointless` function. The variable `z` is accessible anywhere within the pointless function.
What does the following code print? def chair(): pp = 99 return pp chair() print(pp)	This code raises a `NameError` exception with the following message: `name 'pp' is not defined`. The `pp` variable is defined in the `chair()` function, so it has a local scope can can only be accessed in the `chair()` function. `pp` cannot be accessed outside of the `chair()` function.
What does the following code print? ii = 50 def fan(): ii = 100 return ii print(fan())	`100` is printed. The `ii` variable is initially defined in the global scope and then redefined in the local scope of the `fan()` function. The local scope is used when there is a collision with a variable of the same name in the global scope.
What does the following code print? qq = 3 def bike(): qq = 7 bike() print(qq)	`3` is printed. When a global variable is reassigned in the local scope of a function, the reassignment only holds within the local scope. The variable goes back to the global value when the code returns the global scope.
What does the following code print? nn = 9 if True: nn = 16 print(nn)	`16` is printed. `nn` is initially assigned to `9` in the global scope. `nn` is then reassigned to `16` in the code block associated with an `if` statement. `if` statements don't convert the code to local scope like function definitions. `if` statements keep the existing scope.
What does the following code print? cc = 2 if False: cc = 66 def helmet(): if True: cc = 40 helmet() print(cc)	`2` is printed. `cc` is initially assigned to `2`. The `if False` statement evaluates to `False`, so the `cc = 66` reassignment never takes place. The reassignment inside the `helmet()` function does take place, but in the local scope, not the global scope. When the `cc` variable is accessed in the global scope, the value remains unchanged at `2`.